ANSWERS: 1
  • I assume these are the sides of a triangle. In any triangle, the sum of the lengths of any 2 sides is greater than the length of the third side. So, AB + BD > AD and AB + AD > BD and BD + AD > AB (5y - 4) + (7y + 3) > 20y - 9 (5y - 4) + (20y - 9) > (7y + 3) (7y + 3) + (20y - 9) > (5y - 4) 12y - 1 > 20y - 9 25y - 13 > 7y + 3 27y - 6 > 5y - 4 18y > 16 8 > 8y 22y > 2 y > 8/9 y < 1 y > 1/11 These conditions are all satisfied if and only if 8/9 < y < 1

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