ANSWERS: 1
  • 3 men can be chosen from 5 men in 5C3 ways i.e. 5!/3!2! => 10 ways 2 women can be chosen from 4 women in 4C2 ways i.e. 4!/2!2! = 6 ways Choice of men and women are independent so we have 10 x 6 = 60 ways In total we are choosing 5 people from 9 people => 9C5 ways i.e. 9!/5!4! = 630 Hence, probability is 60/630 = 2/21 => 9.5% :)>

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