ANSWERS: 2
  • Assuming the probabilities are independant (the suppliers do not source from the same distributor) the probability is 0.3(probability A delivers on time)+0.5(probability B delivers on time)-0.3x0.5(probability both deliver on time as this probability has been counted twice so far)=0.3+0.5-0.15=0.65 Alternative method: 0.3x[1-0.5](probability that A delivers on time but B does not)+0.5x[1-0.3](probability that B delivers on time but A does not)+0.3x0.5(probability both deliver on time)=0.3x0.5+0.5x0.7+0.3x0.5=0.15+0.35+0.15=0.65
  • The probability of at least 1 supplier delivering on time is simply 1 minus the probability that neither delivers on time... this is the simplest way to calculate it. It gives us 1 - (0.7 * 0.5) = 0.65.

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