by porkchopteach on October 5th, 2006

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I need to know how to determine the escape speed for earth, given a specific density for Earth. Is there anyone who can assist with this please?

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by archimedes on November 13th, 2009
vesc= SQRT(8piGpR^2/3) G=6.673E-11 8 pi= 8*3.141592654... R =56373002.24 meters...p is density which is p=M/(1.3333PiR^3) ..where the mass of earth is 5.9736E24 kg,s or M=v^2r/2G using a known satelite like the Moon.

Worked out...
SQRT(8*3.1415*6.673E-11*5510*6373002.24*6373002.24/3)=
SQRT(375319151.3/3)=SQRT(125106383.8)=11185.0965 meters per second

also... vesc = velocity of object orbiting surface times the square root of two...

or SQRT2*SQRT(GM/r) where r is Earth's radius...

I'll forget the showing of prooving escape velocity through the speed of light
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- r=6373002.24 not the 56373002.24 my typo gave at first
  
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  by archimedes on November 13th, 2009
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by Roger Kovaciny on October 6th, 2006
Escape velocity for a ballistic missile (one which uses up all its fuel) is 25,000 mile per hour, otherwise it would either fall back to earth or go into orbit. If you had an unlimited supply of fuel--if, say, someone developed a practical nuclear rocket motor--you wouldn't have to go that fast.
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I need to know how to determine the escape speed for earth, given a specific density for Earth. Is there anyone who can assist with this please?

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