I need to know how to determine the escape speed for earth, given a specific density for Earth. Is there anyone who can assist with this please?
by 
porkchopteach
ANSWERS: 2
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Escape velocity for a ballistic missile (one which uses up all its fuel) is 25,000 mile per hour, otherwise it would either fall back to earth or go into orbit. If you had an unlimited supply of fuel--if, say, someone developed a practical nuclear rocket motor--you wouldn't have to go that fast.
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vesc= SQRT(8piGpR^2/3) G=6.673E-11 8 pi= 8*3.141592654... R =56373002.24 meters...p is density which is p=M/(1.3333PiR^3) ..where the mass of earth is 5.9736E24 kg,s or M=v^2r/2G using a known satelite like the Moon. Worked out... SQRT(8*3.1415*6.673E-11*5510*6373002.24*6373002.24/3)= SQRT(375319151.3/3)=SQRT(125106383.8)=11185.0965 meters per second also... vesc = velocity of object orbiting surface times the square root of two... or SQRT2*SQRT(GM/r) where r is Earth's radius... I'll forget the showing of prooving escape velocity through the speed of light
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