Runner on 1st. Batter/runner gets a walk to 1st. Now runner going to 2nd. The player from 1st to 2nd runs and oversteps the bag.(Not attempting to go to third.) Can the runner going to 2nd get tagged out by a thrown ball from catcher to 2nd base?
by 
Anonymous
ANSWERS: 6
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No.
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Edited: On a bases on balls situation, it is a dead play and players are allowed to advance without penalty. sorry, misread the question.
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No. It is a free play. If the runner does not turn to third, the runner can not be tagged out for over stepping the bag.
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Rule 7.04(b) Comment: A runner forced to advance without liability to be put out may advance past the base to which he is entitled only at his peril. If such a runner, forced to advance, is put out for the third out before a preceding runner, also forced to advance, touches home plate, the run shall score. Play. Two out, bases full, batter WALKS but runner from second is overzealous and runs past third base toward home and is tagged out on a throw by the catcher......"
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I can't believe all of the WRONG answers!!! The ball is live on a walk and the runner originally on first is only protected to second. If he steps off the base he is liable to be tagged out!
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For those of you who think the ball is dead on a base on balls, consider why the umpire will not let the coach go to the mound until the base runners are at the bases and all play is stopped. That ball is ALIVE. Ask Ryan Theriot of the Cubs, he was running on a 3-2 count, Lee walked, he slid and the catcher threw to second, Theriot overslid 2nd and was tagged with a LIVE ball and the ump gunned him. Out three, next inning.
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