Probability of passing written exam is 88% and the probability of passing the driving exam is 83%. What is the probability of someone picked at random to pass both?
by 
Anonymous
ANSWERS: 3
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88/100 * 83/100 = 7304/10000 = 73.04%
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0% You either study for the test or you don't. You don't draw out of a hat to pass a test, silly.
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they have to pass the driven AND the written p(d) = .88 p(w) = .83 assume the two events are independent p(d&w)= p(d)*p(w)=.88*.83 = .7304
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