ANSWERS: 1
  • Well, it's approximate. If each base path is 70 ft., the right triangle formed by the pitcher's mound would be very close to a 50-50-70 triangle, since 50^2 + 50^2 = 5000, and 70^ = 4900. So therefore pitcher's mound is approximately equidistant from all points of the square formed by the base paths. If half of a diagonal of the square is 50 ft., the full diagonal is 100 ft.

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