How do u solve 3x squared y to the -1 divided by 2x multiplyed by 10x squared y divided by 3y to the -3?
by 
abbey16
ANSWERS: 3
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15x/1/9y
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Could do with some brackets in that. Is 3x squared y to the -1 supposed to be (3x)^2 y^-1 or (3x^2 y)^-1 or 3 x^2 y^-1 or ...? I'm going to assume you meant this: (3 x^2 y^-1 / 2 x) * (10 x^2 y / 3y^-3) Here you have division and also negative powers. It's easiest to convert the equation to leave division and positive powers, or multiplication and negative powers. I think multiplication and negative powers is easier: So wherever you divide by B you change that to multiplied by B^-1 (3 x^2 y^-1 / 2 x) * (10 x^2 y / 3y^-3) becomes 3 x^2 y^-1 2^-1 x^-1 10 x^2 y 3^-1 y^3 Group the factors together: numbers then x then y: 3 3^-1 2^-1 10 x^2 x^-1 x^2 y^-1 y y^3 now add up the powers: 3 3^-1 is 3^1 3^-1 which is 3^0 which is 1. x^2 x^-1 is x^1 and so on. 2^-1 10 x^3 y^3 2^-1 is (1/2) converting back from negative powers. 5 x^3 y^3 This is the basic plan, but your answer will depend on where those brackets went.
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Andrew Jackson (Try Math.com)
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