ANSWERS: 1
  • Normalize the equations to produce quadratic formulae, then resolve by substituting the factors into the quadratic equation: First equation... x^2-3x=-6x-1 (original) : x^2+3x+1=0 (normalized) quadratic formula is applied by substitution: x=(-3+sqrt(3^2-4*1*1))/2*1 (first substitution) then reduced in successive steps: x=(-3+sqrt(9-4))/2 . x+=(-3+sqrt(5))/2 (the answers, not further reduceable) x-=(-3-sqrt(5))/2 Second equation... x^2-10x-1=-10 (add 10 to each side to get zero on the right-hand side) : x^2-10x+9=0 . x=(10+sqrt(100-4*1*9))/2*1 (substitute into quadratic formula) x=(10+sqrt(100-36))/2 ( and reduce in successive steps) x=(10+sqrt(64))/2 x+=(10+8)/2 x+=18/2 x+=9 . x-=(10-8)/2 x-=2/2 x-=1

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