ANSWERS: 1
  • When determining if a fifth order system is stable, neutrally stable or unstable given the poles in the form of A[+-]Bj and C[+-]Dj as given above. If A+B, A-B, C+D and C-D are all positive, then the system is stable. If one of these is negative, it is unstable. Lastly, if exactly two of these are negative, it is neutrally stable. In this case: A+B=-4, A-B=-10, C+D=2, C-D=-6. -4, -10, 2 ,-6. Therefore, since one and only one of the outputs is negative; the system is unstable.

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