ANSWERS: 2
  • The established value of g used for calculations is 9.8 meters/sec./sec. or 32.15 ft./sec./sec. The acceleration component value for the case of initial velocity = 0 and final velocity = 128mph for a time interval of 3.5 seconds is determined by the following equation: acceleration = ((128mile/hour x 5280feet/mile)/(3600seconds/hour))/3.5 seconds = 53.638095238095238095238095238095ft./sec./sec., where the acceleration component is constant throughout the 3.5 second time interval. Therefore, the G-force is found by dividing the acceleration value determined above by the established value of g: (53.638095238095238095238095238095ft./sec./sec)/(32.15ft./sec./sec.) = 1.6683699918536621491520402873436 LESS THAN TWO G's! (Note: this acceleration calculation only relates to the change in velocity from 0 to 128mph in a straight line--other G-forces related to changes in direction can only be calculated if presently unknown (to me anyway) parameters such as rate of change of direction in which direction at what velocity are known.)
  • I think it has nearly 4G's when it goes soaring to the sky.

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