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  • Chemgeek77
    First step: calculate the molecular weight (MW) of beryllium iodide. Go to the periodic table and find the MW of each element present Be: 9.012 g/mol I: 126.90447 g/mol Now add up the MW for each element 9.012 g/mol + 2(126.90447 g/mol) = 262.8 g/mol Now that you have the total MW for the molecule you will multiply the # of moles you have of the molecule by this to get the # grams (0.02 moles)( 262.8 g/mol) = 5.26 g of BeI2
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