What is the speed of the earth relative to the sun i.e. its rate of change of radius?
by 
carte_blanche
ANSWERS: 3
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usually it won't change the radius, if that happens every year wouldn't be 365.25 days, it will keep growing or shrinking.
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Earth’s orbit is nearly circular its eccentricity is 0.0167. (Eccentricity is a measure of how an orbit deviates from circular. It can also be interpreted as the fraction of the distance along the semimajor axis at which the focus lies. A perfectly circular orbit has an eccentricity of zero; higher numbers indicate more elliptical orbits.) We assume Earth's orbit is circular because, one its a close approximation and two it makes questions like yours easier to answer. acceleration=G*m1/r(2) G=gravitational constant=6.67E-11 m(3)kg(-1)s(-2) m1=mass of sun (1.00 E30) kg r=distance to the sun = 1.5E11 m acceleration = 6.67E-11 m(3)kg(-1)s(-2) * (1.00 E30) m / [ (1.5E11 m) * (1.5E11 m)] Answer = 5.8987E-03 ms(-2)
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1) "Aphelion 152,097,701 km 1.0167103335 AU Perihelion 147,098,074 km 0.9832898912 AU" Source and further information: http://en.wikipedia.org/wiki/Earth The difference is: 152,097,701 km - 147,098,074 km = 4,999,627 km There is 6 months time (or about 182 days) between aphelion and perihelion. So the average velocity for the change in radius is: 4,999,627/182 = 27,470 km/day = 1,144 km/h = 320 m/s 2) If you want to know the variation of the average distance from the Earth to the Sun, it varies very slowly: http://en.wikipedia.org/wiki/Red_giant#The_Sun_as_a_red_giant http://www.physicsforums.com/showthread.php?t=172738
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