• You mean (2x-2)/(x^2-x-2) ? The denominator has roots at -1 and 2 The numerator has a root at x=1 There are discontinities if the denomiator has a root and the numerator does not (or if the denominator has a higher order root than the numerator). Therefore there are discontinuties at x=-1 and x=2. No there is no limit. But maybe you stated the question wrong.

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