The height of an object thrown in the air is given by h = t2 – 7t + 3, where h is in feet and t is the time in seconds the object has been in motion. At what time (to the nearest tenth) is the object 10 feet in the air?
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Anonymous
ANSWERS: 2
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10 = t^2 - 7t + 3 -10 t^2 - 7t - 7 = 0 factor your quadratic, complete the square, or use the quadratic formula. Since the time must be positive, @ 7.8875seconds http://www.1728.com/quadratc.htm I'd check your formula, though. The formula I was taught is: h = 9.8t - 2t^2 (this is in meters) h = 32t - 2t^2 (this is in feet)
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Step 1. Substitute into . Step 2. Then, which is quadratic equation with two solutions. The final quadratic equation is after subtracting 10 from both sides of the equation. Step 3. To solve, use the quadratic formula given as where a=1, b=-7, and c=-7 Selecting the positive time is 7.9 seconds Step 4. ANSWER: The time is 7.9 seconds.
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