ANSWERS: 1
  • Its now late aug so I guess the exam is over. However an answer:- Presumably the 0.7 = moles per litre and that the acid is monoprotic since pH is 2.96, The H+ conc is 10^-2.96 and so the conjugate base is 10^-2.96 Ka is (10^-2.96)^2/ 0.7 Ka = 10^-5.92/7X10^-1 Ka = 10^-4.92/7 = 1.43 X 10^-5.92 Ka = 1.72X106-6 pKa = -log10 1.72 X10^-6 pKa = about 5.28

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