ANSWERS: 2
  • Let P(x) be the probability of getting x heads. Then it's P(0) + P(2) + P(4) + P(6) + P(8). Since it's a binomial distribution, we know P(x) = n! / (k! * (n-k)!) * p^k * (1-p)^(n-k) Plug things in: P(0) = 8! / (0! * 8!) * (2/3)^0 * (1/3)^8 = 1 * 1 * (1/3)^8 = 1 / 6561 I think you can do the rest.
  • if (2/3) is the probability for heads then: P(i heads) = nCi (1/3)^(n-i) (2/3)^i So put n=8 and add the results for P(0),P(2),P(4),P(6),P(8) There is formula for that, but it's not worth working out.

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