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You're reading A level maths; Edexcel; S1. Question: P(A) = 0.6, P(B) = 0.3 and P(A U B) = 0.8, find P(A n B). Why does this make sense? I thought P(A U B) was calculated as P(A) + P(B) - P(AnB), but clearly this doesn't work. Answer states P(A n B) = 0.1
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its alrite, i got it all TOTALLY wrong. i can see where i messed up. i thought P(AnB) meant P(A)*P(B), and so obviously i thought P(AnB) would have equalled 0.12
honestly, iv bin stuck on that page for 2 hours, i felt SO silly when i realised where i went wrong. thanx anyway =]
by mak on April 21st, 2008
Ah hah. P(AnB) = P(A)*P(B) ... if A and B are independent. You have therefore deduced that A and B are not completely independent!
Specifically, if A has happened, then P(B|A) is 0.1/0.6 = 1/6 which is lower than P(B), so A helps prevent B happening in some way.
by Quirkie on April 21st, 2008
yes! lol. i hav jus reached that section of th buk
by mak on April 21st, 2008
I just did this question. But how do you calculate the next one ? (A' n B) i cant get my head around how to do it ...
by Scottishdode on May 14th, 2009