by Anonymous on March 28th, 2008

Anonymous

Question

Help answer this question below.

If f(x) = sqrx+4 and the domain of f is all real numbers x greater then -4, what is the range of f? A. all real numbers except 0 B. all real numbers > -4 C. all real numbers > -2 D. all real numbers > 0 E. all real numbers > 2 how do i solve this?

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Answers. 2 helpful answers below.

  • by Quirkie on March 28th, 2008

    Quirkie

    I the best way to approach this kind of problem is to sketch the function.

    The domain is the part of the x-axis which is used by the function: only sketch the function for this part of the x-axis.

    Now draw a thick black line on the y axis wherever part of the function is at that height.

    The values of y form the range of the function.

    You sometimes have to find turning points of the function to find the values exactly. But not for this question.

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  • by iwnit on March 28th, 2008

    iwnit

    We must know what you are here exactly trying to say to solve this.

    What does "sqr" mean here? It could eventually mean:
    - square
    - square root
    Whichever function is represented with "sqr", a more correct mathematic notation would be either:
    sqr(x) + 4
    or
    sqr(x + 4)
    According to the normal rules of mathematic notation, only the first choice would be possible.

    However, following possibility could explain the domain definition:
    f(x) = squareroot(x + 4)
    The reason is that the squareroot is only defined for positive numbers, what means:
    x + 4 >= 0
    x >= -4

    Anyway, we have at least following cases:
    1. "f(x) = squareroot(x + 4)"
    2. "f(x) = square(x + 4)"
    3. "f(x) = squareroot(x) + 4"
    4. "f(x) = square(x) + 4"

    Further discussion does not really make sense if we don't know the exact formulation.
    Again, according to the normal rules of mathematic notation, only the last two options would be possible.

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