What is the square-root of "i"? ("i" being the square-root of -1)
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rahian2k is for world alien domination
ANSWERS: 2
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Like most numbers it has two square roots: (√2+i√2)/2 and (-√2-i√2)/2 You can check by multiplying and collecting terms.
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I think xprofessor's answer is correct, but that answer is full of question marks on my browser. Here's my version: +/- (1+i)/sqrt(2) Proof: (1+i)^2 = 1^2 + 2*1*i + i^2 = 2*i sqrt(2)^2 = 2 So ((1+i)/sqrt(2))^2 = 2*i/2 = i
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