If a column of fresh water 100m high was released through a 3mm diameter hole in the bottom, what would be the velocity of the ejected water (assuming standard temperature and pressure)?
by 
Anonymous
ANSWERS: 1
-
This problem is called "Flow Through an Orifice". First I will define the following variables: V = velocity of the ejected water, meters per second C = coefficient of velocity, which is different for different shapes of openings; for a round, sharp-edged opening it is 0.98 g = acceleration of gravity, 9.81 meters per second squared h = height of the fluid, meters The solution is: V = C x SQRT(2gh) That is, V = C times the square root of (2gh) For this particular problem, V = 0.98 x SQRT(2 x 9.81 x 100) = 43.4 m/s Note that V is independent of viscosity, the fluid density, and of the size of the hole. (From Marks' Standard Handbook for Mechanical Engineers)
RELATED QUESTIONS
Copyright 2023, Wired Ivy, LLC