What is the geography of Roosevelt, Utah?

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Roosevelt is located at 40Â°17'55" LatitudeNorth, 109Â°59'39" LongitudeWest (40.298721, -109.994035). According to the United States Census Bureau, the city has a total area of 13.6 km sq (5.2 square miles), all of it land. Source: http://en.wikipedia.org/wiki/Roosevelt%2C_Utah

Roosevelt is located at 40Â°17'55" LatitudeNorth, 109Â°59'39" LongitudeWest (40.298721, -109.994035). According to the United States Census Bureau, the city has a total area of 13.6 km sq (5.2 square miles), all of it land. Source: http://en.wikipedia.org/wiki/Roosevelt%2C_Utah

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