ANSWERS: 1
  • The latent heat of fusion of ice is 333.55 j/g (joules per gram) which can also be written as 333.55 kj/kg (kilojoules per kilogram) Since there are 40kg of ice to melt it will take: 40 x 333.55 kj = 13342 kilojoules (or 13342000 joules) Some tables list the latent heat of fusion of ice as 334 j/g in which case the answer would be: 40 x 334 kj = 13360 kilojoules (or 13360000 joules)

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