What grade do you learn this in? That is some wild stuff!!! OMGosh!! Are you kidding me? I wouldn't even know where to start!!! ROFL!!! Good Luck friend!! +5

Ok, I will give you some help here. First of all, I will assume that all that you are giving us are the first part of the equations and you have to give products. So the first thing to assume about them is that the positively charged ions will swap places. This means that the metal ions will change places. Second, a number of these are acid base reactions . One product that always comes out of an acid base reaction is water (H2O). (HX + YOH --> YX + HOH, aka. H2O) Based on this, you need to determine the charges on each of the ions involved in each equation so, that you can make sure that you have to right number of each in the products. Your chemistry textbook should have a table that lists the various ions and their charges. By keeping these factors in mind, you should be able to figure out what the products of each reaction will be. Once you have these, then you need to balance the equations. This is simply a matter of adding the appropriate multipliers to the front of the molecules to give you the right number of atom on each side of the equation. I will now do the first one to show you how it is done. It will be up to you to do the rest. _Ca(OH)2 + _HF -> This is an acid-base reaction. So, I know that one product will be H2O. The other product must consist of the remaining ions, Ca and F. Further more, I know, and you could look them up to find out, that H has a 1+ charge and OH has a 1- charge. Therefore, Ca must be 2+ and F must be 1-. So, when they come together, there must be two F for every Ca. Therefore, the other product must be CaF2. So, this gives us _Ca(OH)2 + _HF -> _CaF2 + _H2O Now we make sure that we have the same numbers of ions on each side of the equation. On the left we have one Ca and on the right is one Ca. So, that is good. On the Left we have two O's and on the right we have one O. So, we need to multiply H2O by two. _Ca(OH)2 + _HF -> _CaF2 + 2H2O Now we have the same number of O on each side. However, now we have three H on the left (two in the Ca(OH)2 and one in HF) and four H on the right. So, we still need another H from someplace. Additionally, we have on F on the left and two on the right. So, we also need another F. The way we can get the additional H and F is to multiply HF by two. This give us Ca(OH)2 + 2HF -> CaF2 + 2H2O Now we have the same number of each atom on each side of the equation. So, the equation is now balanced. This how it is done. Now go and do the rest. If you will come back and leave your answers as a comment on this answer. Then I will tell you if you have them right.

Glenn Blaylock has the most helpful answer by far. But I would say that given that you evidently have 4 more days with which to learn the material, you would be better served by getting some one-on-one help from your teacher about this in order to bring you up to speed. http://answers.yahoo.com/question/index;_ylt=Ais2arm13yPEZabVh7NBz2rty6IX;_ylv=3?qid=20091013134309AAUDcIJ http://answers.yahoo.com/question/index;_ylt=ApDP9m.U.vpYFsNU2Vd4Z.fty6IX;_ylv=3?qid=20091013123246AAdTRc4 The goal isn't to get your homework done (thought that IS a short term goal). The ultimate goal is for you to understand the process enough to pass an exam on the material later. Study Glenn Blaylock's answer and then get some help from your teacher. That's what teachers are for. Good luck! Let us know how you do!