ANSWERS: 1
  • luckily, this question doesn't ask for the field at a point somewhere to the right or left of the y axis. Because of this, the problem is much simpler than it could have been. starting with the basics: E = Kq/r^2. What this means is that for each small "dq" on the y axis, it will give a small dE equal to Kdq/r^2, or Kdq/(y + 3)^2 in this case. Luckily, we know the charge density as a function of y. Namely, D = -2.3 microCoulombs/meter for all y. From that, we know that dq = -2.3 dy microCoulombs. integrating -2.3 x 10^-6 K dy/(y + 3)^2 between y = 0 and infinity, you will get the answer (I'm too lazy to do the integral, but it'll be of form C/(y +3)).

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