Given 3.1 grams of CuSO4: a. How many moles of CuSO4 is that? b. How many Cu molecules is that? c. How many moles of Cu are in the sample? d. How many moles of O are in the sample? e. What is the mass of SO4 in the sample?
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Aerli666
ANSWERS: 1
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To help your understanding statrt with What does one mole of CuSO4 weigh .. Mole of Cu=63.5 S=32 O4=16x4 so sum it up =159.5grams .. a. How many moles is 3.1g = 3.1/159.5 = 0.0188 moles b. How many molecules .. = gmoles times 6.02x10^23 = 0.0188 x 6.02x10^23 =1.132x10^22 c. How many moles of Cu .. note one mole Cu for each CuSO4 so.. 0.0188 moles of Cu d. How many moles of O .. note 4 mole O for each mole CuSO4 so 4x0.0188=0.0752 moles O e. Mass of SO4 .. start with mol wts SO4 = 32 + 4x16 = 96 .. CuSO4 is 159.5 so the mass fraction is 96/159.5 = 0.602 take this times the 3.1 grams of CuSO4 = 3.1 x0.602= 1.866 g Understand this and chemistry is easy .. good luck...
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