1) "Standard solution is a chemical term which describes a solution of known concentration. The concentration of the solution is normally expressed in units of moles per Liter (mol/L, often abbreviated to M for molarity). Standard solutions are normally used in titrations to determine the concentration of a substance in solution." Source and further information: http://en.wikipedia.org/wiki/Standard_solution 2) "The mole (symbol: mol) is a unit of amount of substance: it is an SI base unit, and one of the few units used to measure this physical quantity. The name "mole" was coined in German (as Mol) by Wilhelm Ostwald in 1893, although the related concept of equivalent mass had been in use at least a century earlier. The name is assumed to be derived from the word Molekül (molecule). The first usage in English dates from 1897, in a work translated from German. The names gram-atom and gram-molecule have also been used in the same sense as "mole", but these names are now obsolete. The mole is defined as the amount of substance of a system which contains as many "elemental entities" (e.g., atoms, molecules, ions, electrons) as there are atoms in 12 g of carbon-12. Hence: - one mole of iron contains the same number of atoms as one mole of gold; - one mole of benzene contains the same number of molecules as one mole of water; - the number of atoms in one mole of iron is equal to the number of molecules in one mole of water." Source and further information: http://en.wikipedia.org/wiki/Mole_(unit%29 3) "Properties Molecular formula NaOH Molar mass 39.997 g/mol" Source and further information: http://en.wikipedia.org/wiki/NaOH With this information, I am sure you can find the answer...

The way to go about this problem is as follows: 1 M NaOH = 1molNaOH/1Lsolvent that means that for every 1L of water there is 1 mol of Sodium Hydroxide. So now the question is how much is in 100mL = .1L? 1mol/1L=xmol/.1L x=1*.1=.1mol x=.1mol how many grams is that? Since we are looking for mass. We know NaOH is 40g/mol so we can take .1mol(40g/mol) moles cancels and we will be left with grams. 4 grams of NaOH will be in 100mL of solution.