What number is larger, the product of the multiples of 5 that are between 7 and 37 or the product of the multiples of 6 that are between 7 and 37?
by 
thenextmiahamm
ANSWERS: 2
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wow. How else would you do this one except by brute force? Lets see, of 5: 10*15*20*25*30*35... is > or < than of 6: 12*18*24*30*36... I'm going to take a guess that the product of the multiples of 5 is larger since there is one more factor in the product... Let's calculate and find out: The factors of 5: 78.75 x 10^6 The factors of 6: 5.599 x 10^6 Yup. 5 wins because there is one more factor to multiply - and that factor has a power of 10
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Good question, sassafrass. I used brute force also. I did it a bit differently: Product-5s = (5*2)*(5*3)*(5*4)*(5*5)*(5*6)*(5*7) Product-6s = (6*2)*(6*3)*(6*4)*(6*5)*(6*6) Product-5s = 7!(5^6) Product-6s = 6!(6^5) Product-5s = (5040)(15625) Product-6s = (720)(7776) Product-5s = 78,750,000 Product-6s = 5,598,720
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