Select C.

It depends how many choices there are for each question - and how many questions there are. ok - here's why: if the test is only one question long (which it mustn't be, since he said "answers" not answer, and also because he said that you don't know ANY answer AT ALL, then the simple 3rd grade fraction math above would be correct. However, let's try a test with 10 questions, with only 2 choices each. Now that should increase your odds of acing the test. (to 50% according to some of you). For simplicity's sake, let's say the correct answers are all As. Let's say the method you choose for "randomly" selecting the answer is a coin flip. You decide that if it's heads, you'll choose A, and if it's tails, you'll choose B. That's totally random. And to beat these odds, you would have to flip heads 10 times in a row. The chances of that are FAR less than 50%. Is it making sense now? Or did you really mean to ask this question referring to only one test question? I am starting to feel silly that I'm the only person who thought it out beyond the math I did at age 8. I didn't think someone would bother to ask "what are your odds of guessing a multiple choice question correctly" - but kudos if you managed to stump me by making me overthink the most simplistic question I've ever seen on AB! lol ;-)

It depends how many choices there are to an individual question. 3-about 33% 4-25% 5-20% 6-about 16.67% and so on..

The other answers hint at this, but the all-purpose formula theoretically is for x number of choices, the chance of getting it right is 1/x. Practically, however, if the last answer is "None/All of the above" or "A and C" or something like that, then you're better off going with that answer. Simply put, if you're going for only one answer all the way through, then your best bet is to pick the last answer.

One in 3 roughly and going up pro rata.Or maybe I should say down pro rata 33% 25% ETC Depending on amount of selections and number of questions Unless you are a lucky monkey and manage to hit a few extras for a grade one pass, Sorry bit of a bandbox of mine i do not like multiple choice

This is in response to jbarbie23's answer. Lets say we have a test and each question has two choices (A or B). For question 1, the chance of getting it right is 50%. For question 2, the chance of getting it right is 50%. For question 3, the chance of getting it right is 50%. The chance of getting all of the questions (1-3) correct would be 50% * 50% * 50% = 12.5% By ticking the boxes at random it is likely that the person taking the test would get 50% of their answers correct and 50% of their answers incorrect.