by 
Quirkie
ANSWERS: 23
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0 to the power of 0 is the same as saying 0 divided by 0. So, see my answer to this question http://www.answerbag.com/c_view.php/427#q_11865 In respnce to CheeseDude, it is too the same thing. Powers of 1 or more mean that you multiply a number by itself that many time. In other words, n^1 = n, n^2 = n * n, n^3 = n * n * n, etc. Powers that are less than 1 mean that you divide such that n^0 = n/n, n^-1 = n/n/n, etc. Therefore, 0^0 = 0/0. Thus my answer.
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Anything to the power of zero is 1 and zero to the power of anything is zero. As 0 to the power of zero takes both of these cases it is not mathematically defined
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0^0 can be either 1 or 0. However, it is usually defined as 1. http://mathforum.org/dr.math/faq/faq.0.to.0.power.html
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0^0 is defined as 1.
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0^0 can be written as 0^(x-x) or (0^x)/(0^x) . We know 0^x is 0 if x is not equal to zero. So, 0^0 comes out to be 0/0 which is indeterminate. It means that this value cannot be determined.
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I do not know for certain, but as a general rule n^0 = 1. I would strongly argue that 0^0 is 1, however. You could test it graphically, I guess, y=x^0 y=1 for all values of x... hmmmmmm
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In most cases it is reasonable to define it to be 1. In some contexts it may be 0 or undefined. The famous mathematician and computer scientist Donald Knuth explains in one of his books that 0^0 can be seen as special case - of x^0 (in which case it should be 1, because x^0 = 1 holds already for all other x) - of 0^x (in which case it should be 0, because 0^x=0 is true for all x>0) But he then points out that the function x^0 appears quite often in mathematics, for example in the Binomial Theorem, whereas the function 0^x is utterly unimportant. Therefore 0^0 should be seen as a special case of x^0, and hence it makes sense to set 0^0=1.
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Zero
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Good question. The answer is undefined. In some cases zero is the better answer, in other cases one is the better answer. You need more information.
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Zero to any power is zero. Anything to the power of zero is zero.
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0^0 = undefined Usually something to the power of 0 is 1 because going up in powers means multiplying by the base and going down in powers means dividing by the base. Going up: 3^1 = 3 3^2 = 3*3 = 9 3^3 = 9*3 = 27 etc. Going down: 3^3 = 27 3^2 = 27/3 = 9 3^1 = 9/3 = 3 3^0 = 3/3 (base divided by itself) = 1 Now let's apply that to 0: 0^1 = 0 0^0 = 0/0 = undefined (anything divided by 0 is undefined)
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NO. ALL OF THESE ARE WRONG. Any number to the 0 power is NEVER zero. Zero to the zero power is NOT undefined. Any number OTHER than zero "powered" by zero is undefined. But, If ZERO is powered to ZERO it is INDETERMINATE, INDETERMINATE, INDETERMINATE!!
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1
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It is mathematically undefined; anything to the power of 0 makes 1, 0 raised to anything it makes 0 thus, since these contradict each other mathematicians, have labeled it as undefined.
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Zero,my classmate Dana Ikeda would say,"0/0=0",she also said. It may be one, but 0/0 could =1.0x0=0 0/0=?
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Infinite.
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i am confused.i tried to calculate 0^0 but my calculator says "math error" which means no solution.so i guess it should be infinity.
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Conclusion : [ 0^0 ] = 0 or 1 If, zero = number [^^^] = Definition of Liuhui Brahmagupta = [ ( 1 - 1 ) = ( 0 ) ] = [ ( Living Zero ) = ( Dead Zero ) ] = [ (0_) = (_0) ] [ 0 ÷ 0 ] = [ (_0) ÷ (_0) ] = [ (_0) ] = [ 0 ] [ 0 ÷ 0 ] = [ (0_) ÷ (_0) ] = [ (_0) ] = [ 0 ] [ 0 ÷ 0 ] = [ (_0) ÷ (0_) ] = [ (_0) ] = [ 0 ] [ 0 ÷ 0 ] = [ (0_) ÷ (0_) ] = [ 1 ] [ 0 ÷ 0 ] = [ (_0) ÷ (_0) ] = [ (_0) ] = [ 0 ] [ 0 ÷ 0 ] = [ ( 1 - 1 ) ÷ (_0) ] = [ (_0) ] = [ 0 ] [ 0 ÷ 0 ] = [ (_0) ÷ ( 1 - 1 ) ] = [ (_0) ] = [ 0 ] [ 0 ÷ 0 ] = [ ( 1 - 1 ) ÷ ( 1 - 1 ) ] = [ 1 ] [ 0^0 ] = [ (_0)^(_0) ] = [ (_0) ] = [ 0 ] [ 0^0 ] = [ (_0)^(0_) ] = [ (_0) ] = [ 0 ] [ 0^0 ] = [ (0_)^(_0) ] = [ (_0) ] = [ 0 ] [ 0^0 ] = [ (0_)^(0_) ] = [ 1 ] [ 0^0 ] = [ (_0)^(_0) ] = [ (_0) ] = [ 0 ] [ 0^0 ] = [ (_0)^( 1 - 1 ) ] = [ (_0) ] = [ 0 ] [ 0^0 ] = [ ( 1 - 1 )^(_0) ] = [ (_0) ] = [ 0 ] [ 0^0 ] = [ ( 1 - 1 )^( 1 - 1 ) ] = [ 1 ] [ 0^0 ] = [ 0 ÷ 0 ]^[ 0 ÷ 0 ] = (_0)^(_0) = (_0) = 0 [ 0^0 ] = [ 0 ÷ 0 ]^[ 0 ÷ 0 ] = (_0)^1 = (_0) = 0 [ 0^0 ] = [ 0 ÷ 0 ]^[ 0 ÷ 0 ] = 1^(_0) = (_0) = 0 [ 0^0 ] = [ 0 ÷ 0 ]^[ 0 ÷ 0 ] = 1^1 = 1 Coupdetat.net (2009.04.04)
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0^0 is undefined, just as n/0 is undefined. That's the "most likely" answer. ==================================== Addendum: "The debate has been going on at least since the early 1800s. At that time, most mathematicians agreed that 0^0 = 1, but in 1821 Cauchy listed 0^0 along with expressions like 0/0 in a table of undefined forms." ~Wikipedia discussion: http://en.wikipedia.org/wiki/0%5E0#Zero_to_the_zero_power On the same page, skip down to "Treatment in programming languages and calculators": http://en.wikipedia.org/wiki/0%5E0#Treatment_in_programming_languages_and_calculators (Various calculators and programming languages treat 0^0 differently.)
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The answer is 1. Anything to the power of 0 is 1.
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if 0 to the power of 0 is 0 then would this rule apply? (x^x)(x^y)=x^(x+y) x^(x+y) must be greater than or equal to x^x x^(x+y) must be greater than or equal to x^y works with every number but 0, when zero=one. (0^0)(0^1)=0^(0+1)=0^1=0, yet 0^0=1? (1^1)(1^0)=1^(1+0)=1^1=1, 1^0=1, 1^1=1 (2^2)(2^0)=2^(2+0)=2^2=4, 2^0=1, 2^2=4 (2^2)(2^1)=2^(2+1)=2^3=8, 2^2=4, 2^1=2
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I think its a cute lil' anime smiley face! ^_^
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Undefined. You can't tell unless you know that it is part of a greater function (eg. x^0 or 0^x). Then you have to look at how the function works in the real world. Is it continuous? (or should it be continuous?) Then use the answer that makes it continuous. If not, then it is still undefined. Don't rule out having two answers ( eg 0 and 1). The short answer is that 0^0 is undefined. You need more information.
Glenn Blaylock 
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