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by Makatak on November 7th, 2008

Makatak

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Help answer this question below.

A triangle ABC has vertices at A(4,1) and B(9,6). The vertex C lies along the line y=(1/2)x-1. If the length of BC is 5, prove mathematically that there are two possible points for vertex C and find their co-ordinates?

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Answers. 2 helpful answers below.

  • by Farino on November 8th, 2008

    Farino

    In green you have the coordinates A & B.
    In blue you have y = x/2 - 1.
    In magenta you have a cirle with radius 5 and centred at B.
    Granted, the circle is not accurate but it indicates that the two points possible along y that will give a triangle with the distance between B & C as 5 will be (14,6); 14*.5 - 1 = 6 & (6,2); 6*.5 - 1 = 2.

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  • by engineer is Terminator on November 8th, 2008

    engineer is Terminator

    The two points are (10,4) and (6,2)

    Solve for the distance between B and C.

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You're reading A triangle ABC has vertices at A(4,1) and B(9,6). The vertex C lies along the line y=(1/2)x-1. If the length of BC is 5, prove mathematically that there are two possible points for vertex C and find their co-ordinates?

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