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by Jeztyr - whispering in the ears of kings on August 26th, 2008
No. On the left hand side you've got a y and a couple of x's. On the right hand side you've not *any* x's. So they went somewhere...
I think what you should have gotten was:
9(y+3)(3x-1)
The next question is... why?
See how (3x-1) is common to both terms on the left hand side? That means the left hand side can be written as
(9y+27)(3x-1)
From there we can can see that in the first bracket, 9 and 27 are both divisible by 9, so we take 9 out of the brackets:
9(y+3)(3x-1) and Bob's your uncle.
by Anonymous on August 26th, 2008
yea thats what my teacher gave us but i will try that thanks
by AbsolutValu on August 26th, 2008
Is the problem correct? It is a feasible question to answer if that's what you mean.
For example: try plugging in y = 0 and solving for x.
which linear equations are also functions, why?
a)y= -x + 1
b)x= -5
c)y = 2
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