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I'm having trouble visualizing what you mean here. Do you mean you fold both squares in half, and sew them together 1/4" from the diagonal, and then cut along the diagonal? Or do you (for some odd reason) sew a line 1/4" from the diagonal on each square, then cut on the diagonal, leaving you four triangles not sewn together at all? If they are sewn together, you have two right triangles of 1 5/8" (1 7/8 - 1/4) each from each former square. Each will be half the area of a 1 5/8" square. If you need to find the hypotenuse, take the square root of 2*(1 5/8)^2. However, if you are not sewing the triangles together, all you have done is cut the original squares along the diagonal, and sewn a line on them. So you still have right triangles of 1 7/8". Each will be half the area of a 1 7/8" square. Hope this helps!
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