Looking for formula to calculate length of base of isosceles triangle given vertex angle and length of legs -- surfing without luck -- please help
thanx in advance
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Anonymous
ANSWERS: 3
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Split it into right triangles and use sine rules.
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a/sin(A) = b/sin(B) Split the triangle down the middle into two smaller triangles and use the law of sines to figure it out.
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The simplest way to solve this problem is to use the law of cosines. In this case, the law of sines cannot be applied directly, but the law of cosines can. The law of cosines states: a^2=b^2+c^2-2bccosα a is the length of the side you want to find, b and c are the lengths of the legs of the triangle, and α is the measure of the angle opposite a (the angle between the legs).
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