by Anonymous on June 2nd, 2004

Anonymous

Question

Help answer this question below.

In a game of 8-ball Call Shot, prior to the break a player calls the 8 ball in the side pocket, then breaks and makes the 8 ball in the corner pocket. Does this player win or lose the game immediately, or neither?

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Answers. 5 helpful answers below.

  • by IsZatSo on October 18th, 2005

    IsZatSo

    According to tournament rules,

    4.8 8-BALL POCKETED ON THE BREAK
    If the 8-ball is pocketed on the break, breaker may ask for a re-rack or have the 8-ball spotted and continue shooting. If the breaker scratches while pocketing the 8-ball on the break, the incoming player has the option of a re-rack or having the 8-ball spotted and begin shooting with ball in hand behind the head string.

    All the official rules for call shot eight ball can be found at

    http://www.bca-pool.com/play/tournaments/rules/rls_8bl.shtml

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  • by answerman on November 9th, 2008

    answerman

    In league play, 8 on the break without scratching is a win, regardless of where it was called. Said player is a fool for thinking they can predict the 8, and the pocket it will fall in. I'll bet against him heavy all night long.

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  • by buzz123456 on March 7th, 2007

    buzz123456

    He loses, first it did not go where called, second does not matter what he calls eight can only go in on its own.

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  • by CaRbOnPrOdUcK is Baccuss on November 10th, 2010

    CaRbOnPrOdUcK is  Baccuss

    i'M pretty sure he automatically loses. If you were playing billieards the rules are a little different. But Pool the eight ball has to be last.

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  • by my2cents--Vote for Paul on November 10th, 2010

    my2cents--Vote for Paul

    Win.

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