ANSWERS: 6
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the chances that he had drawn a white pair would only be 1/4...the same as if he had drawn a black pair 1/4.
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There was no chance. There are 3 white socks and 1 black.
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It doesnt matter to him, he is blind so he has the best excuse for odd socks if somebody dared to comment.
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socks: (b,b,b,b)(b,b,b,w)(b,b,w,w)(b,w,w,w)(w,w,w,w) (b,b,b,w)The chance that he draws out black socks: 3/4 x 2/3 = 1/2 (b,b,w,w)The chance that he draws out black socks: 2/4 x 1/3 = 1/6 But he already had a pair of white socks. My answer is like Morgenstern : There is no chance for him to draw out a pair of black socks.
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This question is not properly written. There is no way he could have taken out two black socks because there is only 1 black sock in his drawer.
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If the chance is 1/2, there are either 2 or 3 white socks: - not 0 or 1 or there could not be a pair - not 4 or the chance would be 1. If there were 2 white socks, the chance to draws a pair of white socks would be: - 2/4 = 1/2 to take a white as the first sock - 1/3 to take a white as the second sock afterwards Total chance: (1/2) * (1/3)= 1/6 As the chance was 1/2, this does not apply. If there were 3 white socks, the chance to draws a pair of white socks would be: - 3/4 to take a white as the first sock - 2/3 to take a white as the second sock afterwards Total chance: (3/4) * (2/3)= 2/4 = 1/2 This applies. If 3 of the 4 socks are white, you cannot draw a pair of black socks. So the chances are 0.
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