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by Farino on August 8th, 2007
There is a similar question:
http://www.answerbag.com/q_view/87251
Height of the dive is irrelevant, it is the speed fo which one hits the water. This speed will give you the height of a 66m free-fall. Seeing I do not know the speed I must go backwards from the height:
v = end velocity
u = start velocity
a = acceleration (usually 9.8 m/s^2 due to gravity in vertical senarios)
s = distance
v^2 = u^2 + 2as
v^2 = 0^2 + 2*9.8*66
v^2 = 1293.6
v ~= 35.967 m/s
Maximum speed is just under 36 m/s (or almost exactly 118 fps)
by ChaiCustard on August 9th, 2007
I think it will vary a bit depending on water turbulence, and body shape. With the ideal body shape, and low surface tension (eg air bubbles) Id guess you could get a lot higher with only severe injuries, (no death)
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Comments
That should take care of it - Good!
by tomsims on August 9th, 2007