by Iroquois on October 8th, 2011

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How good are you at Algebra? If you are as good as you say you are, than solve: 3x-2(x-3)-[x-2(5-x)]

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by phil656565 on October 8th, 2011
-2x+16, all simple algebra, not one to challenge anyones algebra skills
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- and those words may bite me in the ass, but im 99% sure im right, hell i better be ive taken all calculus courses and am taking differential equations and linear algebra right now.
  
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  by phil656565 on October 8th, 2011
- How did you get that? I know algebra, but I can't remember how to factor the x's when they are by themselves?? Please explain
  
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  by Premortem dichotomy on October 8th, 2011
- Ok, well the first thing you want to do is multiply whats inside the parenthases with the number outside it, remember to distribute the negative. So -2(x-3)= -2x+6 and -2(5-x)= -10+2x. Then simplify whats outside the brackets 3x-2x+6=x+6. Then simplify whats inside the brackets x-10+2x=3x+10. Distribute your negative through the brackets so you get -3x+10, then add it all together x+6-3x+10=-2x+16. Hope this helps.
  
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  by phil656565 on October 8th, 2011
- Yes! The distributive property! I almost forgot. Thanks for reminding me. :D
  
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  by Premortem dichotomy on October 8th, 2011
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by WarHorseLeBron on October 9th, 2011
3x-2x+6-x+10-2x

-2x+16
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by Icameback4now on October 8th, 2011
Not tonight honey I have a headache....hehehe
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by The Chief on October 9th, 2011
Solve it?

Perhaps I could...IF you had actually written an equation. But you haven't, so the best that anyone can do is reduce what you have to simpler terms.

That would be:

3x-2x+6-x+10-2x

16-2x
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by Outta-here on October 9th, 2011
One cannot solve an equation if it is not an equation....that is the solution.
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by Snatchsquach on October 8th, 2011
OK...I got it....It's...It's....Uhmmm....6 apples left over?
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- But the train left Boston at 4 PM!
  
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  by JPsgirl on October 9th, 2011
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by Crowsnest on October 11th, 2011
Unfortunatelly, Im not good enough, sorry.

But you'll surely be lucky :-)
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by goodbye on October 8th, 2011
three somethings subtract two and multiply one something minus three and subtract all that shit from this shit as follows:1 something minus two and then multiplied five minus that same something..Hope this helps :O)
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by JPsgirl on October 9th, 2011
Having trouble in school are ya?
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How good are you at Algebra? If you are as good as you say you are, than solve: 3x-2(x-3)-[x-2(5-x)]

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how do you simplify this expression: (x^3+3x^2-2)+(5x^3+x+8)-(9x^3-x^2+4)

Your help will be greatly appreciated (x-7) / 3 - (4/3)=? x-7 over 3 minus 4 over 3 (x^2) / (x+3) + 9/(x+3)=? x squared over x+3 Plus 9 over x+3 (x^2+2x) / 3x - (x^2+5x+6) / 3x =? x squared plus 2x over 3x minus x squared plus 5x plus 6 over 3x

According to the Upper & Lower Bound Rules, f(x)=3x^8+x^7+5x^6+4x^5+x^4+2x^3+x^2-5x+7 should have upper & lower bounds of 1 and -1, respectively. However, it has a real zero beyond these boundaries. Are there limitations to the rules and what are they?

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Can u tell me if this is right?1. (3+5)(2x^2 - 7x + 4) answer (3x +5)(2x^2 -7x +4)=(3x)(2x^2 -7x +4 ) +(5)(2x^2 -7x + 4 ) =(3x)(2x^2) -(3x)(7x)+(3x)(4)+(5)(2x^2)-(5)(7x)+(5)(… -21x^2 +12x +10^2 -35x +20 =6x^3-11x^2 -23x +20

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How good are you at Algebra? If you are as good as you say you are, than solve: 3x-2(x-3)-[x-2(5-x)]

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