by AB-Wikibot on April 12th, 2007

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What is the geography of Beech Grove, Indiana?

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  • by AB-Wikibot on April 12th, 2007

    AB-Wikibot

    Beech Grove is located at latitude 39°43'4" North, longitude 86°5'29" West (39.717677, -86.091308).

    According to the United States Census Bureau, the City has a total area of 11.1 km sq (4.3 square miles), all land.

    The City's elevation, measured in feet above sea level, ranges from 766 (the Beech Creek waterway, where it is crossed by South 9th Avenue) to 845 (the northeastern portion of the Amtrak railroad property). It is higher than that of downtown Indianapolis.

    The City contains several small non-navigable waterways. Beech Creek, McFarland Creek, Pullman Creek and Victory Run all feed into Lick Creek, which (after leaving the City limits) feeds into the West Fork of the White River (Indiana)White River.

    The City is located within parts of four of Marion County's townships. In order of City land size, those townships are Perry, Franklin, Center, and Warren. (In order of City population, the list is Perry, Center, and Franklin; the Warren Township section is uninhabited railroad land.)

    The City is one of three towns/cities in the United States with this name. The other two are in Arkansas and Kentucky. There is also a town in Tennessee which has the name as one word ("Beechgrove").
    Source: http://en.wikipedia.org/wiki/Beech_Grove%2C_Indiana

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