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by iwnit on February 5th, 2010
There is no solution.
The greater "rectangle" of length 10 cm is the square of side 10 cm.
Its area is 100 cm^2.
All other rectangles of length 10 cm have a smaller area.
On the other hand, for a width of 10 cm, all rectangles of length > 12 cm have an area > 120 cm^2
by ZiggyStardust on February 3rd, 2010
10cmX12cm==120CM^2
by One mans opinion on February 2nd, 2010
Write the equation in the correct form with "W" as the variable for the width
10*W=>120
/10=/10 Divide both sides by 10
W=>12 Width must be greater than 12cm
MAth homework help in description below
by Anonymous on October 9th, 2011
| 1 person likes this
346 is the given number must be divisible by 3. what is the missing greatest number?
by Franz_P on September 26th, 2011
| 1 person likes this
Would you watch a video called 2 elephants 1 cup?
by randylikesyourbutt on October 28th, 2011
| 1 person likes this
Can you do this for me smallest to largest!! 0.3 , 0.109 , 0.1
0.19 , 0.903 , 0.9 , 0.91 , 0.09
by Elisha_S7421 on September 29th, 2011
| 1 person likes this
use the factor theorem to determine whether or not h(x) is a factor of f(x)
h(x) = x + 1; f(x)= x^3 - 4x^2 + 3x + 8
by Anonymous on September 27th, 2011
| 2 people like this
You're reading The length of a rectangle is 10cm.What width will make the area greater then 120cm(squared)?
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