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Help answer this question below.
x^2 - 2x - 15
x^2 - 2x - 15 is of the form x^2 + bx + c.
To factor a quadratic trinomial of the form x^2 + bx + c, find two integer factors of 'c' whose sum is 'b'.
If no such integers exist, we say the trinomial is not factorable.
b = -2 and c = -15
Note: When 'b' is positive, the factors are positive, and when 'b' is negative, the factors are negative.
x^2 - 2x - 15 = (x + __)(x + __)
Look for factors of -15 whose sum is -2.
Factors of -15 Sum
1 and -15 -14
3 and -5 -2
The factors needed are 3 and -5.
x^2 - 2x - 15 = (x + 3)(x + (-5))
= (x + 3)(x - 5)
Check:
(x + 3)(x - 5) = x . x + 3 . x + (-5) . x + 3 . (-5) [FOIL Method]
= x^2 + 3x - 5x - 15
= x^2 - 2x - 15 [The product is the original trinomial]"
X^2 = (X ) (X )
whats multiplies to -15, adds too -2
+5, -3
(x-5)(x+3)
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You're reading how do i solve x^2-2x-15=0?
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