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Help answer this question below.
2.23 x 10^-2 = 0.0223 mol
1 mol of ideal gas at STP = 22.4L => 22.4L/mol
Nitrogen is very close to an ideal gas
22.4 x 0.00223 = 0.049952 L
you can only really quote this to the 3rd number due to the accuracy of your other values so 0.0500 L or 50mL
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You're reading What volume of a beaker contains exactly 2.23 times 10 to the negative second power mole of nitrogen gas at stp?
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