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by crazy on November 13th, 2009
height = 16.53ft
distance = 66.125ft
by archimedes on November 13th, 2009
It is not 32.2 feet per second squared, it is per second per second. Meaning an increase of 32.2 ft per second every second until equilibrium AKA terminal velocity. The answers ahead are correct.
d=v^2/g...or v^2sin(2@)/g but 45 degress is 90 when doubled thus 1.
height is v^2*(sin@)^2/2g
When did Isaac Newton make the three laws of motion?
by Answerbag Staff on May 19th, 2010
| 1 person likes this
Does frictional force acting on an object depend on the amount of force(opposite direction to the friction) applied to the object??
by Inddiggo:)) on June 23rd, 2011
| 2 people like this
please solve this problem
by Ripan on June 16th, 2011
| 1 person likes this
By following the Principle of Homogeneity, can we say S directly proportional to t² and t in S=ut +1/2 at² ?
'u' and 'a' are constant
by Asish_J on August 15th, 2011
| 1 person likes this
what will happen if i hit solid ground head first at 11m/s(40kmph)?
by shehzaanvirani on May 13th, 2011
| 3 people like this
You're reading A ball is shot at an angle of 45 degrees into the air with initial velocity of 46 ft/sec. Assuming no air resistance, how high does it go? How far away does it land? Hint: The acceleration due to gravity is 32 ft per second squared. Thank you!
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