by Ask.Listen.Learn. on November 8th, 2009

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Can you solve this problem for X and show the work? 3x^2-7=-31 (Negative 31 and 3x is raised to the second power)

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  • by Anonymous on November 10th, 2009

    Anonymous

    3X^2-7= -31, 3X^2= -24, X^2= -24/3, X^2= -8, X= SQR -8, which is not a rational number.

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  • by Inactive member. on November 9th, 2009

    Inactive member.

    3x^2 - 7 = -31
    3x^2 = -31 +7
    3x^2 = -24
    x^2 = -24/3
    x^2 = -8
    There is no solution, except when using imaginary numbers. In which case, you could say...
    x = sqrt of -8
    or
    x = sqrt of 8i
    or
    x = sqrt of 4*2*i which equals 2 sqrt of 2i

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  • by iwnit on November 10th, 2009

    iwnit

    1) No, because the equation is about x, not about X.


    2) Assuming a typo:
    3x^2-7=-31
    3x^2=7-31=-24
    x^2=-8

    There are no real solutions. There are imaginary ones, though.

    Further information:
    http://en.wikipedia.org/wiki/Quadratic_equation

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