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by beastdevices on November 4th, 2009

beastdevices

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I have a 5kilo object that I need to turn to turn. It is shaped like a pyramid and will be connected at the tip to the shaft of a motor. The height of the pyramid is 4in and width 10in. What inertia and torque do I need to turn this around shaft?

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  • by Jahono on November 5th, 2009

    Jahono

    From: http://www.mitcalc.com/en/ui/tformulas.pdf
    Four side pyramid - Moment of inertia; Mass:
    I = m/20 * (A^2 + B^2)
    m = 1/3 * A * B * H * Ro
    ……[I-Moment of inertia; A-Side; B-Side; H-High; Ro-Density

    http://ocw.mit.edu/NR/rdonlyres/Aeronautics-and-Astronautics/16-07Fall-2004/4440D65E-123C-483F-90CB-81F7F040E673/0/d23.pdf Gives you a detailed overview with some relevant examples on page 10 (depending how in depth you want to get).

    MOst other sources recommend integrating the volume in respect to the rotational axis.

    To get torque from inertia:
    a = T/I
    a = angular acceleration
    T = torque
    I = inertia

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