by LANA on October 31st, 2009

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WHAT IS THE PROCESS OF SOLVING: the 2nd 2 is squared but I did not know how to type the 2 as squared & the -4 is a negative 4 not a minus 4 & IF x=2 and y= -4 (negative 4) 2x2(squared) + 3xy -4y2 (squared) =

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WHAT IS THE PROCESS OF SOLVING: the 2nd 2 is squared but I did not know how to type the 2 as squared & the -4 is a negative 4 not a minus 4 & IF x=2 and y= -4 (negative 4) 2x2(squared) + 3xy -4y2 (squared) =

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HOW TO SOLVE THIS PROBLEM: THE 2ND 2'S IN THIS PROBLEM STAND FOR SQUARED DUE TO I DO NOT KNOW HOW TO TYPE THE # SQUARED. X=2 Y=-4(NEGATIVE 4). 2X2(this 2 stands for squared) + 3xy-4y2 (negative 4 NOT minus & again 2 stands for squared) 2x(2)+3xy-4(2)

HOW TO SOLVE THIS PROBLEM: THE 2ND 2'S IN THIS PROBLEM STAND FOR SQUARED DUE TO I DO NOT KNOW HOW TO TYPE THE # SQUARED. X=2 Y=-4(NEGATIVE 4). 2X2(this 2 stands for squared) + 3xy-4y2 (negative 4 NOT minus & 2 stands for squared) 2x(2)+3xy-4(2) =

Your help will be greatly appreciated (x-7) / 3 - (4/3)=? x-7 over 3 minus 4 over 3 (x^2) / (x+3) + 9/(x+3)=? x squared over x+3 Plus 9 over x+3 (x^2+2x) / 3x - (x^2+5x+6) / 3x =? x squared plus 2x over 3x minus x squared plus 5x plus 6 over 3x

Geometry problems 1)The graph of which equation is an ellipse? A. 2x^2-3y^2=6 B. 3x^2+3y^2=12 2) x/2=3/y is A.circle B .an ellispse C.a hyperbola D.A line 3)The graph of the euqation 4x^2+4y^2=25 is A. circle B .an ellispse C. a hyperbola D.p

how do you solve for x if x is squared on both sides of the equation? Example: 4x^2 = x^2 + 36. Subtracting x^2 or dividing doesn't work.

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WHAT IS THE PROCESS OF SOLVING: the 2nd 2 is squared but I did not know how to type the 2 as squared & the -4 is a negative 4 not a minus 4 & IF x=2 and y= -4 (negative 4) 2x2(squared) + 3xy -4y2 (squared) =

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