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Help answer this question below.
this formula comes from the idea that (at equilibrium) energy is equally distributed in all available modes, right? i think that is still true in QM - so no change
throw in relativity if you want to have some fun
Well nothing really, the energy equation you have there is for an ideal gas that has no real connection to the quantum level. The energy of the individual electrons is instead given by E = (h^2k/4pi.m.a^2)n^2 so unless you are confining your ideal gas to an area of about a nanometer then your 3/2 RT is a perfect indicator of the kinetic energy.
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