by Alexander on October 28th, 2009

Alexander

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Classical non-quantum monoatomic ideal gasses all have energy strictly equal to E=3/2 RT, fact. How will kinetic energy change if we throw in quantum mechanics?

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  • by purplecows on March 23rd, 2010

    purplecows

    this formula comes from the idea that (at equilibrium) energy is equally distributed in all available modes, right? i think that is still true in QM - so no change

    throw in relativity if you want to have some fun

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  • by Anonymous on November 1st, 2009

    Anonymous

    Well nothing really, the energy equation you have there is for an ideal gas that has no real connection to the quantum level. The energy of the individual electrons is instead given by E = (h^2k/4pi.m.a^2)n^2 so unless you are confining your ideal gas to an area of about a nanometer then your 3/2 RT is a perfect indicator of the kinetic energy.

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