ANSWERS: 1
  • I think it looks trickier than it is. (2x^2-15)/(x^2+x-6) = (x+1)/(x+3) + (x-3)/(x-2) (2x^2-15)/(x+3)(x-2) = [(x+1)(x-2)+(x-3)(x+3)]/(x+3)(x-2) 2x^2-15 = (x+1)(x-2) + (x-3)(x+3) 2x^2-15 = x^2 - x - 2 + x^2 - 9 2x^2-15 = 2x^2 - x - 11 -15 = -x-11 -4 = -x 4 = x

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