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by smiiles on August 23rd, 2009

smiiles

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How to prepare 0.5 molar AgNO3?What is the formula/calculation methode involved in it? Please clear it?

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  • by Jahono on August 24th, 2009

    Jahono

    M = m/n
    M = molar wieght (grams/mol)
    m = mass (grams)
    n = number of moles

    so to calc weight of 1 mol of AgNO3 m = Mn = M x 1
    where M (AgNO3) = M(Ag) + M(N) + 3xM(O)
    = 107.9 + 14 + 3 x 16
    = 169.9 g

    Note: the AgNO3 has to be a anhydrous powder.

    Add half the 169.9 grams of AgNO3 to 1 Litre of water and you get a 0.5mol/L AgNO3 solution, or 0.5 molar AgNO3

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