by LadyGigi on August 13th, 2009

LadyGigi

Question

Help answer this question below.

Solve for the tension in each of the cables attached to the traffic light. http://i32.tinypic.com/15ogkjo.jpg Please help me. The information is all in the picture of the worksheet.

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Answers. 2 helpful answers below.

  • by H on August 13th, 2009

    H

    Its quite easy -

    Simple resolving of forces, much like the question has already stated.

    You have the definitions,

    0.866 T1 - 0.766 T2 = 0
    0.8 (?) T1 + 0.643 T2 = 880


    Resolve those two to find T1 and T2, it should be very straightforward :)

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  • by engineer is Terminator on August 16th, 2009

    engineer is Terminator

    Actually your answer is there in your question.You have already solved it.Just need to find out the T1 and T2 value from the given equation.
    The horizontal force are in equilibrium
    So T1Cos30 = T2Cos40
    Now T1Sin30+T2Sin40 addup to counterbalance the weight of the Light.=100x9.8 m/s^2
    Remember the Unit of acceleration is m/sec^2 not m/sec^3.
    My Physics teacher never awarded my batchmates any marks for wrong units though,they deliverd right answers.
    I think you can solve it out Now.

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What is the tension in each of the cables
What is the tension in each of the cables
0 866t1 0 766t2 0
Solve for tension in each of the cables attached to the traffic light
Solve for the tension in each of the cables attached to the traffic light